Find the element which appears maximum number of times in an array

import java.util.Arrays;
public class MyClass {
    public static void main(String args[]) {
        int max = 0, count = 0;
        int[] a={1,2,3,4,8,8,9,8,3,3,5,3,4,5,6,8};

        //sorting array   
        for(int i=0;i<a.length;i++){

            for(int j=i+1;j<a.length;j++){
                int first=a[i];
                int second=a[j];
                int temp=0;

                if(first>second){

                    temp=first;
                    a[i]=second;
                    a[j]=temp;

                }
            }
        }
        //  Arrays.sort(a);
        //finding highest number with times
        for(int i=0;i<a.length;i++){
            int num=a[i];

            if(max==num){
                count++;
            }else if(max<num){
                max=num;
                count=1;

            }
        }

        System.out.println("max number : " + max);
        System.out.println("times: " + count);
        
    }
}

OUTPUT

max number : 9
times: 1